Integrand size = 18, antiderivative size = 36 \[ \int \frac {1}{x \sqrt {2+5 x-3 x^2}} \, dx=-\frac {\text {arctanh}\left (\frac {4+5 x}{2 \sqrt {2} \sqrt {2+5 x-3 x^2}}\right )}{\sqrt {2}} \]
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Time = 0.01 (sec) , antiderivative size = 36, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.111, Rules used = {738, 212} \[ \int \frac {1}{x \sqrt {2+5 x-3 x^2}} \, dx=-\frac {\text {arctanh}\left (\frac {5 x+4}{2 \sqrt {2} \sqrt {-3 x^2+5 x+2}}\right )}{\sqrt {2}} \]
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Rule 212
Rule 738
Rubi steps \begin{align*} \text {integral}& = -\left (2 \text {Subst}\left (\int \frac {1}{8-x^2} \, dx,x,\frac {4+5 x}{\sqrt {2+5 x-3 x^2}}\right )\right ) \\ & = -\frac {\tanh ^{-1}\left (\frac {4+5 x}{2 \sqrt {2} \sqrt {2+5 x-3 x^2}}\right )}{\sqrt {2}} \\ \end{align*}
Time = 0.07 (sec) , antiderivative size = 27, normalized size of antiderivative = 0.75 \[ \int \frac {1}{x \sqrt {2+5 x-3 x^2}} \, dx=\sqrt {2} \text {arctanh}\left (\frac {\sqrt {4+10 x-6 x^2}}{-2+x}\right ) \]
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Time = 0.25 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.81
method | result | size |
default | \(-\frac {\operatorname {arctanh}\left (\frac {\left (4+5 x \right ) \sqrt {2}}{4 \sqrt {-3 x^{2}+5 x +2}}\right ) \sqrt {2}}{2}\) | \(29\) |
trager | \(\frac {\operatorname {RootOf}\left (\textit {\_Z}^{2}-2\right ) \ln \left (-\frac {5 \operatorname {RootOf}\left (\textit {\_Z}^{2}-2\right ) x +4 \operatorname {RootOf}\left (\textit {\_Z}^{2}-2\right )-4 \sqrt {-3 x^{2}+5 x +2}}{x}\right )}{2}\) | \(47\) |
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Time = 0.41 (sec) , antiderivative size = 43, normalized size of antiderivative = 1.19 \[ \int \frac {1}{x \sqrt {2+5 x-3 x^2}} \, dx=\frac {1}{4} \, \sqrt {2} \log \left (-\frac {4 \, \sqrt {2} \sqrt {-3 \, x^{2} + 5 \, x + 2} {\left (5 \, x + 4\right )} - x^{2} - 80 \, x - 32}{x^{2}}\right ) \]
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\[ \int \frac {1}{x \sqrt {2+5 x-3 x^2}} \, dx=\int \frac {1}{x \sqrt {- \left (x - 2\right ) \left (3 x + 1\right )}}\, dx \]
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Time = 0.28 (sec) , antiderivative size = 35, normalized size of antiderivative = 0.97 \[ \int \frac {1}{x \sqrt {2+5 x-3 x^2}} \, dx=-\frac {1}{2} \, \sqrt {2} \log \left (\frac {2 \, \sqrt {2} \sqrt {-3 \, x^{2} + 5 \, x + 2}}{{\left | x \right |}} + \frac {4}{{\left | x \right |}} + 5\right ) \]
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Leaf count of result is larger than twice the leaf count of optimal. 84 vs. \(2 (28) = 56\).
Time = 0.30 (sec) , antiderivative size = 84, normalized size of antiderivative = 2.33 \[ \int \frac {1}{x \sqrt {2+5 x-3 x^2}} \, dx=-\frac {1}{6} \, \sqrt {6} \sqrt {3} \log \left (\frac {{\left | -4 \, \sqrt {6} + \frac {10 \, {\left (2 \, \sqrt {3} \sqrt {-3 \, x^{2} + 5 \, x + 2} - 7\right )}}{6 \, x - 5} - 14 \right |}}{{\left | 4 \, \sqrt {6} + \frac {10 \, {\left (2 \, \sqrt {3} \sqrt {-3 \, x^{2} + 5 \, x + 2} - 7\right )}}{6 \, x - 5} - 14 \right |}}\right ) \]
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Time = 0.29 (sec) , antiderivative size = 29, normalized size of antiderivative = 0.81 \[ \int \frac {1}{x \sqrt {2+5 x-3 x^2}} \, dx=-\frac {\sqrt {2}\,\ln \left (\frac {5\,x+2\,\sqrt {-6\,x^2+10\,x+4}+4}{x}\right )}{2} \]
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